Solving AoC 2018 in 2024
I'm currently working through Advent of Code whenever I get the chance, alongside my day-to-day activities. I chose to start with the 2018 challenges because of the excellent repository by BurntSushi. When else do you get the opportunity to compare your solutions with some of the best?
Day 1 Day 2 Day 3 Day 4 Day 5 Day 6
Day 1 #
My first AoC challenge ever. So far most coding challenges were either on Codewars, Leetcode, or Exercism. I think forcing yourself to do these every once in a while is important, but I have not been very happy with the format of the mentioned options. While I dreaded those, doing AoC challenges is a lot of fun.
use std::collections::HashSet;
use std::fs;
fn main() {
let mut set = HashSet::new();
let message: String = fs::read_to_string("input.txt")
.expect("Could not read content of file.");
let mut sum = 0;
set.insert(0);
loop {
for l in message.lines() {
sum += l.parse::<i32>().expect("Could not parse to type i32");
if set.contains(&sum) {
println!("{}", sum);
return;
}
set.insert(sum);
}
}
}
Day 2 #
I think the code is overall okay. Sort of imperative and not very idiomatic but at this stage, I am happy to get through the challenges. Idiomatic code will come with time. I could have definitely improved variable naming for my HashMap
and HashSet
.
use std::collections::{HashMap, HashSet};
fn main() {
let input = std::fs::read_to_string("input/final.txt").expect("Could not read file");
let result_1 = part_1(&input);
let result_2 = part_2(&input);
println!("Result for Part 1 is {}", result_1);
println!("Result for Part 2 is {}", result_2);
}
fn part_1(input: &str) -> i32 {
let mut two = 0;
let mut three = 0;
for line in input.lines() {
let mut dic = HashMap::new();
let mut set = HashSet::new();
for ch in line.chars() {
dic.entry(ch).and_modify(|ch| *ch += 1).or_insert(1);
}
for count in dic.values() {
if *count == 2 {
set.insert(2);
}
if *count == 3 {
set.insert(3);
}
}
for results in set.iter() {
match *results {
2 => two += 1,
3 => three += 1,
_ => println!("Don't care about the value."),
}
}
}
two * three
}
fn part_2(input: &str) -> String {
let mut result = String::from("");
let mut input_content = Vec::new();
for line in input.lines() {
input_content.push(line);
}
input_content.sort();
for n in 0..input_content.len() - 1 {
let a = input_content[n];
let b = input_content[n + 1];
let count = a.chars().zip(b.chars()).filter(|&(a, b)| a != b).count();
if count == 1 {
result = a
.chars()
.zip(b.chars())
.filter(|&(a, b)| a == b)
.map(|(char1, _)| char1)
.collect();
}
}
result
}
Day 3 #
As you can see, I have a lot of todos left in this challenge that I want to address at some point. Looking at it a few days later, I should have not used index accessing with the vectors. Parsing could see some improvements as well. Ideally I want to make a call to some parsing function that then returns the necessary data for each l in input.lines()
iteration.
use std::{collections::HashSet, fs::read_to_string};
// TODO: Create stryct for a Cell in the matrix
// TODO: Impl the new() and add_id() for struct
// TODO: Split_once()
// TODO: Proper error handling with split once and parse
// TODO: Change direct access via index values, use tuples and destructuring
fn main() {
// TODO: Spread the logic into two parts and create matrix in here
let input = read_to_string("input/final.txt").expect("Could not read file");
let part_1 = part_1(&input);
println!("Result for part 1: {}", part_1);
}
fn part_1(input: &str) -> i32 {
let mut matrix: Vec<Vec<(i32, HashSet<&str>)>> = vec![vec![(0, HashSet::new()); 1000]; 1000];
let mut count = 0;
for l in input.lines() {
let subset: Vec<&str> = l.split(" @ ").collect();
let id = &subset[0][1..];
let coordinates: Vec<&str> = subset[1].split(": ").collect();
let distances: Vec<&str> = coordinates[0].split(',').collect();
let sizes: Vec<&str> = coordinates[1].split('x').collect();
let column_start = distances[0].parse::<usize>().expect("Could not convert");
let row_start = distances[1].parse::<usize>().expect("Could not convert");
let width = sizes[0].parse::<usize>().expect("Could not convert");
let height = sizes[1].parse::<usize>().expect("Could not convert");
let column_end = column_start + width;
let row_end = row_start + height;
(column_start..column_end).for_each(|i| {
(row_start..row_end).for_each(|j| {
matrix[i][j].0 += 1;
matrix[i][j].1.insert(id);
})
});
}
let mut ones: HashSet<&str> = HashSet::new();
let mut twos: HashSet<&str> = HashSet::new();
for row in &matrix {
for element in row {
let count_matrix = element.0;
if count_matrix >= 2 {
count += 1;
twos.extend(&element.1);
}
if count_matrix < 2 {
ones.extend(&element.1);
}
}
}
let result: HashSet<_> = ones.difference(&twos).collect();
println!("{:?}", result);
count
}
Day 4 #
This was a lot of code. Pretty sure the logic between part 1 and part 2 is sort of duplicated, so that should be improved. I'm also not happy about the parsing and splitting to extract the timestamps. I should probably look at regex or a crate like nom.
use std::error::Error;
use std::result;
use std::{collections::HashMap, fs};
type Result<T> = result::Result<T, Box<dyn Error>>;
type GuardSleepFrequency = HashMap<usize, [usize; 60]>;
fn main() -> Result<()> {
let input = fs::read_to_string("input/final.txt")?;
let mut lines: Vec<&str> = input.lines().collect();
// TODO: Handle expect
lines.sort_by_key(|line| extract_date(line).expect("Invalid format"));
// Sleep stats keeps track of Guard Id and minutes sleeping and their count
let mut sleep_stats: GuardSleepFrequency = HashMap::new();
let mut sleep_start = 0usize;
let mut id = 0usize;
// Loops over each line and keeps track of a guard sleep in sleep_stats
for line in &lines {
// Action should be action Type, should have id or None
let (current_minute, action) = parse_line(line)?;
match action {
_ if action.starts_with("Guard ") => {
let (_, id_content) = action
.split_once(" #")
.ok_or("Could not split Guard info")?;
let (guard_id, _) = id_content.split_once(' ').ok_or("Could not split id")?;
id = guard_id.parse::<usize>()?;
}
_ if action.starts_with("falls asleep") => {
sleep_start = current_minute;
}
_ if action.starts_with("wakes up") => {
let minute_sleep_count = sleep_stats.entry(id).or_insert([0; 60]);
if current_minute < sleep_start {
(sleep_start..60).for_each(|m| {
minute_sleep_count[m] += 1;
});
(0..current_minute).for_each(|m| {
minute_sleep_count[m] += 1;
});
} else {
(sleep_start..current_minute).for_each(|m| {
minute_sleep_count[m] += 1;
})
}
}
_ => {}
}
}
match part_1(&sleep_stats) {
Ok(result) => println!("Part 1 result: {}", result),
Err(err) => println!("There was an error in Part 1: {}", err),
};
match part_2(&sleep_stats) {
Ok(result) => println!("Part 2 result: {}", result),
Err(err) => println!("There was an error in Part 2: {}", err),
};
Ok(())
}
fn part_1(frequency: &GuardSleepFrequency) -> Result<usize> {
let mut max_guard_sleeping = 0usize;
let mut sleep_sum = 0usize;
for (k, v) in frequency.iter() {
let current_sum: usize = v.iter().sum();
if current_sum > sleep_sum {
max_guard_sleeping = *k;
sleep_sum = current_sum;
}
}
let minute_frequency = match frequency.get(&max_guard_sleeping) {
Some(freq) => freq,
None => return Err(From::from("Could not retrieve frequency for a guard")),
};
let max_minute = minute_frequency
.iter()
.enumerate()
.max_by_key(|(_, &value)| value)
.map(|(idx, _)| idx)
.ok_or("Could not get maximum minute asleep")?;
Ok(max_guard_sleeping * max_minute)
}
// TODO: This is not very idiomatic. Use flatmap over guard and minutes, enumerate over minutes and
// map them into a tuple of guard, minute, count. Get the max by key of count, and map that into
// count * minute
fn part_2(frequency: &GuardSleepFrequency) -> Result<usize> {
let mut current_max = usize::MIN;
let mut guard = 0usize;
let mut max_minute_idx = 0usize;
for (k, v) in frequency.iter() {
let max_idx = v
.iter()
.enumerate()
.max_by_key(|(_, &value)| value)
.map(|(idx, _)| idx)
.ok_or("Could not get maximum minute asleep")?;
if let Some(minute_count) = frequency.get(k) {
if let Some(minute) = minute_count.get(max_idx) {
if *minute > current_max {
current_max = *minute;
guard = *k;
max_minute_idx = max_idx;
}
}
}
}
Ok(guard * max_minute_idx)
}
fn extract_date(line: &str) -> Result<&str> {
let date = line
.split_once('[')
.and_then(|(_, rest)| rest.split_once(']'))
.map(|(date, _)| date.trim())
.ok_or("Invalid format: date not found in brackets")?;
Ok(date)
}
fn parse_line(line: &str) -> Result<(usize, &str)> {
let minute_hour = line
.split_whitespace()
.nth(1)
.ok_or("Can't split on first whitespace")?;
let minute_str = minute_hour
.trim_end_matches(']')
.split(':')
.nth(1)
.ok_or("Can't split on colon")?;
let minute = minute_str
.parse::<usize>()
.map_err(|_| "Failed to parse into i32".to_string())?;
let action = line
.split("] ")
.nth(1)
.ok_or("Can't split on second whitespace")?;
Ok((minute, action))
}
Day 5 #
I got side-tracked by starting the implementation with a sliding window approach. Turns out that this was not the best idea. I simple stack approach was all I needed. Part 2 felt pretty straight forward. I solved it by looping over a range of 0..26 while grabbing the numerical value of a character via:
let lower = (b'a' + i) as char;
let upper = (b'A' + i) as char;
Lower and upper were then used to compare against the current character.
Performance wise this is not an ideal approach with it's time complexity of O(m*n), where m is the length of the alphabet and n the input size. In our example 26 * 50000. If anyone knows of a solution bringing the iterations down from 1.3m to 50k, please let me know!!
Also got into testing a bit, which was neat.
use std::{error, fs};
type Result<T> = std::result::Result<T, Box<dyn error::Error>>;
fn main() -> Result<()> {
let input = fs::read_to_string("input/final.txt")?.trim().to_string();
match part_1(&input) {
Ok(result) => println!("Part 1 result: {}", result),
Err(err) => return Err(err),
}
match part_2(&input) {
Ok(result) => println!("Part 2 result: {}", result),
Err(err) => return Err(err),
}
Ok(())
}
fn part_1(input: &str) -> Result<usize> {
let cleaned_stack_length = react(input);
Ok(cleaned_stack_length)
}
fn part_2(input: &str) -> Result<i32> {
let mut result = i32::MAX;
for i in 0..26 {
let mut stack = String::from("");
let lower = (b'a' + i) as char;
let upper = (b'A' + i) as char;
for char in input.chars() {
if char != lower && char != upper {
stack.push(char);
}
}
let length = react(&stack);
let length = i32::try_from(length).unwrap();
if length < result {
result = length;
}
}
Ok(result)
}
fn react(input: &str) -> usize {
let mut stack = String::from("");
for char in input.chars() {
if let Some(top) = stack.chars().last() {
if will_units_react(char, top) {
stack.pop();
} else {
stack.push(char);
}
} else {
stack.push(char);
}
}
stack.len()
}
fn will_units_react(x: char, y: char) -> bool {
(x.is_lowercase() && y.is_uppercase() && x.to_ascii_uppercase() == y)
|| (x.is_uppercase() && y.is_lowercase() && x == y.to_ascii_uppercase())
}
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn will_units_react_test() {
assert!(will_units_react('c', 'C'));
assert!(will_units_react('C', 'c'));
assert!(will_units_react('B', 'b'));
assert!(will_units_react('b', 'B'));
}
#[test]
fn will_units_not_react_test() {
assert!(!will_units_react('a', 'a'));
assert!(!will_units_react('B', 'B'));
assert!(!will_units_react('a', 'B'));
assert!(!will_units_react('A', 'b'));
}
}
Day 6 #
Pretty straight forward approach. On this one I had to do a lot of debugging and created visuals to figure out a good approach. Part 2 is replicating the approach in Part 1 and while it led to a quick solution, it should be optimized.
fn part_1(grid: &mut grid<string>, coordinates: &grid<i32>) -> result<i32> {
let mut infinite_values = hashset::new();
for row in 0..grid.len() {
for col in 0..grid[0].len() {
let mut minimum_distance = i32::max;
let mut minimum_index = none;
let mut conflict = false;
for (i, el) in coordinates.iter().enumerate() {
let manhattan_distance =
(row as i32 - el[1]).abs() + (col as i32 - el[0]).abs();
match manhattan_distance.cmp(&minimum_distance) {
ordering::less => {
minimum_distance = manhattan_distance;
minimum_index = some(i);
conflict = false;
}
ordering::equal => {
conflict = true;
}
ordering::greater => {
// do nothing
}
}
}
if conflict {
grid[row][col] = string::from(".");
} else if let some(index) = minimum_index {
let coordinate = (b'a' + index as u8) as char;
grid[row][col] = coordinate.to_string();
}
// check which of the values are infinte
if row == 0
|| row == grid.len() - 1
|| col == 0
|| col == grid[0].len() - 1
{
infinite_values.insert(grid[row][col].to_string());
}
}
}
let mut finite_values: hashmap<string, i32> = hashmap::new();
for row in 0..grid.len() {
for col in 0..grid[0].len() {
if !infinite_values.contains(&grid[row][col]) {
*finite_values
.entry(grid[row][col].to_string())
.or_insert(0) += 1;
}
}
}
let largest_value = finite_values
.iter()
.max_by_key(|&(_, v)| v)
.ok_or("could not find an entry")?;
ok(*largest_value.1)
}
fn part_2(grid: &mut grid<string>, coordinates: &grid<i32>) -> result<i32> {
let mut count = 0;
for row in 0..grid.len() {
for col in 0..grid[0].len() {
let mut distance_total = 0;
for (i, el) in coordinates.iter().enumerate() {
let manhattan_distance =
(row as i32 - el[1]).abs() + (col as i32 - el[0]).abs();
distance_total += manhattan_distance;
}
if distance_total < 10_000 {
count += 1;
}
}
}
Ok(count)
}
Day 7 #
I worked on this challenge when I had a lot of other stuff going on and was only able to finish Part 1.
use std::{collections::HashMap, error::Error, fs, result, u8};
type Result<T> = result::Result<T, Box<dyn Error>>;
type StepMap = HashMap<char, Vec<char>>;
#[derive(Copy, Clone, Debug)]
struct Worker {
remaining_seconds: Option<u8>,
current_char: Option<char>,
}
impl Worker {
fn new() -> Self {
Worker {
remaining_seconds: None,
current_char: None,
}
}
fn busy(&mut self) -> bool {
if let Some(remaining) = self.remaining_seconds {
remaining >= 1
} else {
false
}
}
fn work(&mut self) {
if let Some(mut remaining) = self.remaining_seconds {
remaining -= 1;
}
}
}
fn main() -> Result<()> {
let input = fs::read_to_string("input/final.txt")?;
let mut incoming: StepMap = HashMap::new();
let mut outgoing: StepMap = HashMap::new();
for l in input.lines() {
let (points_to, pointed_at) = parse_line(l);
// The chars that have incoming "pointers"
incoming
.entry(pointed_at)
.and_modify(|e| {
e.push(points_to);
})
.or_insert_with(|| vec![points_to]);
// The chars that have outgoing "pointers"
outgoing
.entry(points_to)
.and_modify(|e| {
e.push(pointed_at);
})
.or_insert_with(|| vec![pointed_at]);
}
match part_1(&incoming, &outgoing) {
Ok(result) => println!("Part 1 result: {}", result),
Err(err) => return Err(err),
}
match part_2(&incoming, &outgoing) {
Ok(result) => println!("Part 2 result: {}", result),
Err(err) => return Err(err),
}
Ok(())
}
fn part_1(incoming: &StepMap, outgoing: &StepMap) -> Result<String> {
let mut available_steps = Vec::new();
let mut completed_steps = Vec::new();
// Find all steps that have no prerequisites
for k in outgoing.keys() {
if !incoming.contains_key(k) {
available_steps.push(*k);
}
}
while !available_steps.is_empty() {
// Sort available steps to always choose alphabetically first
available_steps.sort();
// Take the first available step
let current_step = available_steps.remove(0);
completed_steps.push(current_step);
// If this step has outgoing steps, check which can now be completed
if let Some(next_steps) = outgoing.get(¤t_step) {
for &next_step in next_steps {
// Check if all prerequisites for this next step are completed
if let Some(prereqs) = incoming.get(&next_step) {
if prereqs.iter().all(|p| completed_steps.contains(p)) {
// Only add if not already in available or completed steps
if !available_steps.contains(&next_step)
&& !completed_steps.contains(&next_step)
{
available_steps.push(next_step);
}
}
}
}
}
}
Ok(completed_steps.iter().collect::<String>())
}
// Returns character tuple, at 1: &str from which we point, at 2: &str pointed at
// Index' are guaranteed to exist
fn parse_line(line: &str) -> (char, char) {
let a = line[5..6]
.chars()
.next()
.expect("Expected at least 6 characters in the line");
let b = line[36..37]
.chars()
.next()
.expect("Expected at least 36 characters in the line");
(a, b)
}